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Find the Second Largest Number in a List

·94 words·1 min
len if-else sort()

Helloo,

In this blog I will show you how to find the second largest number in a list.

I’ve included the instruction in my code first you make a list with numbers any order you like then you do (listname).sort() after that use if and else that’s all :))).

#The List
list_b = [6, 1, 3, 5]

#To sort the number in ascending order
list_b.sort()

#If to check if list_b bigger than 1
if len(list_b) > 1:
    print('The second largest value is:', list_b[-2])
#Else in case list_b is smaller than 1    
else:
    print("None")

:3