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Make a Frequency Dictionary From the Element of a List

·145 words·1 min
Dictionary If-Else

Hello, my new challenge is to write a python program that tally’s each letter for example there are 3 a’s, 2 b’s and 5 c’s in the dictionary it shall look like this {“a”: 3, “b”: 2, “c”: 5}

To do this:

  1. make a list it can be numbers if you want
  2. make an empty dictionary
  3. do for-loop
  4. use if statement and if the key not in dictionary add to the dictionary with the default value 1
  5. else/ if in there add 1 to the old key
  6. print the dictionary
#lelement = ["a", "a", "b", "c", "a", "b"]
lelement = [1, 2, 3, 4, 2, 1, 2]
dict = {}

print("New challenge: Make a Frequency Dictionary from the Elements of a List")
for t in lelement:
    #print(t)
    if t not in dict:
        dict[t] = 1
    else:
        dict[t] = dict[t] + 1   

print(dict)

Thank You. :3